Chemistry - Thermodynamics - I Question with Solution | TestHub
ChemistryThermodynamics - IWorkMedium2 minQB
ChemistryMediumsingle choice
Passage / Comprehension
An ideal gas with the adiabatic exponent γ undergoes a process in which its internal energy relates to the volume as U = a·Vα, where a and α are constants.
What is the magnitude of work performed by the gas to increase its internal energy by ΔU?
Options:
Answer:
C
Solution:
For one mole, U = CvT and U = aVα give T = aVα/Cv, so p = RT/V = (R/Cv)·a·V^(α−1) = a(γ−1)V^(α−1), using Cv = R/(γ−1). Work: W = ∫p dV = a(γ−1)·(V₂α − V₁α)/α = ((γ−1)/α)·a(V₂α − V₁α) = ΔU(γ−1)/α, since ΔU = a(V₂α − V₁α). Matches (c).
Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:Work
⏱ 2mℹ️ Source: QB
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