Chemistry - Thermodynamics - I Question with Solution | TestHub

ChemistryThermodynamics - IFirst law of ThermodynamicsEasy2 minPYQ_2020
ChemistryEasysingle choice

Standrad entropies ofX2,Y2andXY3are 60, 40 and 50JK-1mol-1respectively. For the reaction12X2+32Y2↔XY3,ΔH=-30 kJto be at equilibrium, the temperature should be

Options:

Answer:
B
Solution:

As for this reaction12X2+32Y2→XY3
ΔS=∑SP-∑SR
ΔS=50-12×60+32×40=-40 JK-1mol-1
ΔG=ΔH-TΔS
Now as at equilibriumΔG=0
SoΔH-T.ΔS=0
OrT=ΔHΔS=-30×103-40
T=750 K

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:Thermodynamics - ISubtopic:First law of Thermodynamics
⏱ 2mℹ️ Source: PYQ_2020

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