One mole of a gas is heated at constant pressure to raise its temperature by 2 ∘ C . The work done by the system in joules

W = − P Δ V = − n R Δ T = − 1 × 8.314 × 2 = − 16.628 J

Chemistry - Thermodynamics - I Question with Solution | TestHub

ChemistryThermodynamics - IWorkMedium2 minQB

ChemistryMediumsingle choice

One mole of a gas is heated at constant pressure to raise its temperature by $2^{\circ} C$ . The work done by the system in joules

Answer:

Solution:

$W = - P Δ V = - n R Δ T = - 1 \times 8.314 \times 2 = - 16.628 J$

Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:Work

⏱ 2mℹ️ Source: QB

Loading discussions...