Chemistry - Thermodynamics - I Question with Solution | TestHub

ChemistryThermodynamics - IFirst law of ThermodynamicsMedium2 minQB
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One mole of a real gas is subjected to a process from (2 bar, 30 L, 300 K) to (2 bar, 40 L, 500 K). The molar heat capacity of gas at constant volume and constant pressure are 25 and 40 J/K-mol, respectively. What is the change in internal energy of the gas in this process?

Options:

Answer:
A
Solution:

For any substance whose CV is given as a constant, Δ U = n CV Δ T = 1 × 25 × (500 - 300) = 5000 J. The given CP is not needed for Δ U. Matches (a).

Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:First law of Thermodynamics
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