As 1 mole of liquid water is heated from 288 to 308 K, it expands slightly against the atmosphere. Given coefficient of cubic expansion of water is 1.0×10⁻⁴/°C; density of water = 1.0 g cm⁻³ and exter

Question

As 1 mole of liquid water is heated from 288 to 308 K, it expands slightly against the atmosphere. Given coefficient of cubic expansion of water is 1.0×10⁻⁴/°C; density of water = 1.0 g cm⁻³ and external pressure = 1 bar. If the magnitude of work for this process is X J, then the value of X/(4.5×10⁻⁴) is

TestHub · Accepted Answer

V of 1 mol water = 18 cm³ = 18×10⁻⁶ m³. ΔV = V·γ·ΔT = 18×10⁻⁶ × 1×10⁻⁴ × 20 = 3.6×10⁻⁸ m³. W = P e xt·ΔV = 10⁵ × 3.6×10⁻⁸ = 3.6×10⁻³ J. X/(4.5×10⁻⁴) = 3.6×10⁻³/(4.5×10⁻⁴) = 8.

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