Chemistry - Thermodynamics - I Question with Solution | TestHub

ChemistryThermodynamics - IFirst law of ThermodynamicsHard2 minQB

ChemistryHardmultiple choice

Passage / Comprehension

Passage: $Comprehension (Q.1 to Q.8) Use the thermodynamic equation of state (\frac{\partial U}{\partial V})_{T} = T (\frac{\partial P}{\partial T})_{V} - P to answer the following questions for n moles of a gas that obeys P = \frac{n RT}{V} + \frac{β n ^{2}}{V ^{2}} where β is a positive constant and C_{V} is independent of temperature.$

$Δ H$ for the isothermal change from ( $P_{1}$ , $V_{1}$ , $T$ ) to ( $P_{2}$ , $V_{2}$ , $T$ ). (More than one may be correct)

Options:(select one or more)

Answer:

A, C

Solution:

$Δ H = Δ U + Δ (P V)$ with $Δ U = β n^{2} (1/ V_{2} - 1/ V_{1})$ : this is (A).

$P V = n RT + β n^{2} / V$ , and $T$ is constant, so $Δ (P V) = P_{2} V_{2} - P_{1} V_{1} = β n^{2} (1/ V_{2} - 1/ V_{1})$ .

Hence $Δ H = 2 β n^{2} (1/ V_{2} - 1/ V_{1})$ : (C).

(B) misses $Δ U$ . (D) is the heat, not $Δ H$ . Answer: A, C.

Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:First law of Thermodynamics

⏱ 2mℹ️ Source: QB

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