Chemistry - Thermodynamics - I Question with Solution | TestHub
ChemistryThermodynamics - IWorkHard2 minQB
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One mole of a diatomic ideal gas (γ = 7/5) at (P0, V0) is compressed to V0/2 in three different ways: (X) reversible isothermal, (Y) reversible adiabatic, (Z) in one step against a constant external pressure of 2P0. Arrange the three in increasing order of the magnitude of work done on the gas.
Options:
Answer:
C
Solution:
X: w = P0V0 ln 2 = 0.693 P0V0.
Y: P2 = P0 × 21.4 = 2.639 P0, so P2V2 = 1.320 P0V0.
w = (P2V2 - P0V0)/(γ - 1) = 0.320/0.4 P0V0 = 0.799 P0V0.
Z: w = PextΔV = 2P0 × (V0/2) = 1.000 P0V0.
Order: X (0.693) < Y (0.799) < Z (1.000).
Answer: (C).
Stream:JEESubject:ChemistryTopic:Thermodynamics - ISubtopic:Work
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