Calculate the change in enthalpy for he following process at 1 atm(Round off to nearest integer)
H₂O (ℓ ,50℃)→ H₂O (g , 150℃) given that ΔH_vap at 100℃ is 40.7 kJmol^-1
C_p (H₂O ,ℓ ) = 75.0 Jmol^-1K^-1
C_p(H₂O ,g) = 33.3 Jmol^-1K^-1

Question

Calculate the change in enthalpy for he following process at 1 atm(Round off to nearest integer)

H₂O (ℓ ,50℃)→ H₂O (g , 150℃) given that ΔH_vap at 100℃ is 40.7 kJmol^-1

C_p (H₂O ,ℓ ) = 75.0 Jmol^-1K^-1

C_p(H₂O ,g) = 33.3 Jmol^-1K^-1

TestHub · Accepted Answer

H 2 ​ O ( l ) ​ ( 5 0 ∘ C ) → H 2 ​ O ( l ) ​ ( 10 0 ∘ C ) → H 2 ​ O ( g ) ​ ( 10 0 ∘ C ) → H 2 ​ O ( g ) ​ ( 15 0 ∘ C ) Total heat absorbed = Δ temp.rise ​ H ( 50 → 100 ) + Δ vap ​ H + Δ temp.rise ​ H ( 100 → 150 ) ​ = C P ​ Δ T + Δ Vap ​ H + C P ​ Δ T

Chemistry - Thermochemistry Question with Solution | TestHub

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