H + + O H − → H 2 O ; Δ H o = − 57 k J / m o l Δ H ionisation 0 [ HCN ] = 45 kJ / mol . If 200 ml of 10 1 M B a ( O H ) 2 solution is mixed in 500 ml of 10 1 M H CN solution of then heat evolved will be

\displaylines B a ( O H ) 2 + 2 H CN → B a ( CN ) 2 + 2 H 2 O ; Δ H = − 24 k J / m o l Ba(OH) 2 is the limiting reagent heat evolved will be = 24 × 20 × 1 0 − 3 = 48 × 1 0 − 2 kJ 480 Joule

Chemistry - Thermochemistry Question with Solution | TestHub

ChemistryThermochemistryEnthalpy of NeutralisationMedium2 min

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$H^{+} + O H^{-} \to H_{2} O; Δ H^{o} = - 57 k J / m o l$

$Δ H_{ionisation}^{0} [HCN] = 45 kJ / mol$ .

If 200 ml of $\frac{1}{10} M B a (O H)_{2}$ solution is mixed in 500 ml of $\frac{1}{10} M H CN$ solution of then heat evolved will be

Options:

Answer:

Solution:

$\displaylines B a (O H)_{2} + 2 H CN \to B a (CN)_{2} + 2 H_{2} O$ ; $Δ H = - 24 k J / m o l$

Ba(OH)₂ is the limiting reagent

heat evolved will be $= 24 \times 20 \times 1 0^{- 3}$ $= 48 \times 1 0^{- 2} kJ$

480 Joule

Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Neutralisation

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