For which of the following change Δ H ≠ Δ E ? (Where Δ H is change in enthalpy, Δ E is change in internal energy).

Δ H ≠ Δ E in case of N 2 ( g ) + 3 H 2 ( g ) → 2 N H 2 ( g ) as Δ n g is not zero here. In rest other reaction Δ n g is zero so Δ H = Δ E .

Start Free Mock LoginAlready registered? Login here

Chemistry - Thermochemistry Question with Solution | TestHub

ChemistryThermochemistryEnthalpy of ReactionEasy2 minPYQ_2020

ChemistryEasysingle choice

For which of the following change
$Δ H \neq Δ E ?$
(Where $Δ H$ is change in enthalpy, $Δ E$ is change in internal energy).

Options:

Answer:

Solution:

$Δ H \neq Δ E$ in case of $N_{2} (g) + 3 H_{2} (g) \to 2 N H_{2} (g)$ as $Δ n_{g}$ is not zero here. In rest other reaction $Δ n_{g}$ is zero so $Δ H = Δ E$ .

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Reaction

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...