Chemistry - Thermochemistry Question with Solution | TestHub

ChemistryThermochemistryEnthalpy of CombustionHard2 minQB
ChemistryHardnumerical

The carbon dioxide exhaled in the breath of astronaut is often removed from the spacecrafts by reaction with lithium hydroxide.

2LiOH(s) + CO2(g) → Li2CO3(s) + H2O(l)

Assume that each astronaut requires 2820 kJ of energy per day. Further assume that this energy is obtained only from the combustion of glucose into CO2(g) and H2O(l). The standard enthalpies of formation of glucose, CO2 and water are -1260, -395 and -285 kJ/mol, respectively. The minimum mass (in g) of LiOH required per astronaut per day to react completely with all the CO2 produced is

Answer:
287.00
Solution:

ΔHcomb(glucose) = [6(-395) + 6(-285)] - (-1260) = -2820 kJ/mol. Energy needed = 2820 kJ, so nglucose = 1.00 mol and nCO2 = 6.00 mol. LiOH needed = 2 × 6.00 = 12.0 mol = 12.0 × 23.94 ≈ 287 g. Answer: 0287.

Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Combustion
⏱ 2mℹ️ Source: QB

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