Chemistry - Thermochemistry Question with Solution | TestHub
ChemistryThermochemistryEnthalpy of NeutralisationEasy2 minQB
ChemistryEasysingle choice
The enthalpy of neutralisation of HF with NaOH is -68.6 kJ/mol, while that of a strong acid with a strong base is -57.3 kJ/mol. Find the enthalpy of ionisation of HF.
Options:
Answer:
B
Solution:
Neutralisation of HF = ionisation of HF + neutralisation of a strong acid (-57.3 kJ/mol).
-68.6 = ΔHion - 57.3.
ΔHion = -68.6 + 57.3 = -11.3 kJ/mol.
Answer: (B).
Stream:JEESubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Neutralisation
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