Start Free Mock LoginAlready registered? Login here

Chemistry - Thermochemistry Question with Solution | TestHub

ChemistryThermochemistryEnthalpy of ReactionEasy2 minPYQ_2020

ChemistryEasysingle choice

If $E A_{1}$ and $E A_{2}$ for oxygen atom $- 142 k J m o l^{- 1}$ and $+ 844 k J m o l^{- 1}$ . The energy released form $2 O + 2 e^{-} \to 2 O^{-}$ will be

Options:

Answer:

Solution:

$O + e^{-} \to O^{-}$
$Δ H = - 142 k J m o l^{- 1}$
So $2 O + 2 e^{-} \to 2 O^{-}$
$Δ H = 2 \times (- 142)$
$= - 284 k J m o l^{- 1}$

Stream:NTA_ABHYAS_NEETSubject:ChemistryTopic:ThermochemistrySubtopic:Enthalpy of Reaction

⏱ 2mℹ️ Source: PYQ_2020

Doubts & Discussion

Loading discussions...