Chemistry - Stoichiometry Question with Solution | TestHub

Question Explanation: A stoichiometry problem involving a limiting reactant.

Concept: This question is based on Limiting Reactant.

Solution:

$$C+O_2\to C{O}_2$$

Mass: 27 g of C, 88 g of O₂

Moles of C = $\frac{27}{12}=2.25$

Moles of O₂ = $\frac{88}{32}=2.75$ mol

Carbon (C) is the limiting reagent.

Moles of CO₂ produced = moles of C = $\frac{27}{12}=2.25$ mol

Therefore, the volume of CO₂ at STP = $2.25\times 22.4=50.4$ L.

The ratio of C and O in CO₂ = $12:32=3:8$.

Moles of unreacted O₂ = $2.75-2.25=0.5$ mol.

Therefore, the volume of unreacted O₂ at STP = $0.5\times 22.4=11.2$ L.

Final Answer: Option (B, C, D)