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Chemistry - Stoichiometry Question with Solution | TestHub

ChemistryStoichiometryProblems Based on Mixtures, Percentage PurityMedium2 minQB

ChemistryMediumnumerical

A mixture of Xe and $F_{2}$ was heated. A sample of the white solid thus formed reacted with hydrogen to give 112 ml of Xe at 0°C and 1 atm, and the $HF$ formed required 40 ml of 0.5 M - $NaOH$ for complete neutralization. If the molecular formula of the solid is $Xe F_{x}$ , then the value of $x$ is

Answer:

4.00

Solution:

Xe = 112/22400 = 0.005 mol, so $HF$ = 0.005x mol. $NaOH$ = 0.040 × 0.5 = 0.02 mol = $HF$ . So 0.005x = 0.02 $\Rightarrow$ $x$ = 4 ( $Xe F_{4}$ ). Ans: 4.

Stream:JEESubject:ChemistryTopic:StoichiometrySubtopic:Problems Based on Mixtures, Percentage Purity

⏱ 2mℹ️ Source: QB

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