Initial moles of H 2 O 2 in a cylinder are -

Question

Initial moles of H 2 ​ O 2 ​ in a cylinder are -

TestHub · Accepted Answer

Cylinder volume = 3 L = 3000 mL Volume strength of H₂O₂ = 44.8 volumes O₂ requirement = 200 mL/min

Time = 2.8 h = $2.8 \times 60 = 168$ min Conditions: 1 atm, 273 K (so 1 mol gas = 22.4 L) Total O₂ required by patientl:

$200 m L / min \times 168 min = 33600 m L = 33.6 L$ Convert O₂ to moles:

$m o l es O_{2} = \frac{33.6}{22.4} = 1.5 m o l$ Relation between H₂O₂ and O₂:

$2 H_{2} O_{2} \to 2 H_{2} O + O_{2}$

So: 1 mol O₂ comes from 2 mol H₂O₂

$m o l es H_{2} O_{2} d eco m p ose d = 2 \times 1.5 = 3 m o l$ Use volume strength (44.8 volumes) 44.8 volumes means: 1 L solution gives 44.8 L O₂

So in mol terms:

$44.8 L O_{2} = 2 m o l O_{2}$

So: $1 L so l u t i o n co n t ain s H_{2} O_{2} t ha t g i v es 2 m o l O_{2}$

Hence: $1 L so l u t i o n co n t ain s 4 m o l H_{2} O_{2}$

Total H₂O₂ in 3 L solution

$3 \times 4 = 12 m o l$

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