Chemistry - Stoichiometry Question with Solution | TestHub
Match List-I correctly with List-II :
List - I | List - II |
|---|---|
(P) Zn(s) + 2HCl(aq) → ZnCl2 (aq) + H2(g) above reaction is carried out by taking 2 moles each of Zn and HCl | (1) 50% of excess reagent left |
(Q) above reaction is carried out by taking 170 g and 18.25 g HCl ( ) | (2) 22.7 L of gas at STP is liberated |
(R) CaCO3 (s) → CaO(s) + CO2 (g) 100 g CaCO3 is decomposed | (3) 1 moles of solid product is obtained |
(S) 2KClO3 (s) → 2KCl(s) + 3O2 (g) 2/3 moles of KClO3 decomposed | (4) HCl is the limiting reagent |
| (5) None of the reagent is limiting |
Options:
Answer:
Solution:
(P)
Initial mole: 2 2 0 0
Final mole: 0 1 1
Excess reagent left:
Volume of H₂ = 22.4 lit.
Solid product obtained = 1 mole.
Limiting reagent is HCl.
(Q)
Initial mole: 0 0
Final mole: 0
Excess reagent:
Volume of gas = 11.2 lit.
Solid product = mole.
Limiting reagent is HCl.
(R)
Initial mole: 0 0
Final mole: 0 1 1
Excess reagent not present.
Volume of gas = 22.4 lit. at STP.
Solid product is 1 mole.
(S)
Initial mole: 0 0
Final mole: 0 2
No excess reagent left.
Volume of gas = 44.8 lit.
Solid product is mole.