Chemistry - Stoichiometry Question with Solution | TestHub

${\mathrm{K}}_2{\mathrm{CO}}_3\underset{\text{ Steps }}{\overset{\text{ Several }}{\to }}{\mathrm{K}}_2{\mathrm{Zn}}_3{\left[\mathrm{Fe}(\mathrm{CN}{)}_6\right]}_2$

Since C atoms are conserved, applying POAC for C atoms,

Moles of C in ${\mathrm{K}}_2{\mathrm{CO}}_3=$ Moles of C in ${\mathrm{K}}_2{\mathrm{Zn}}_3{\left[\mathrm{Fe}(\mathrm{CN}{)}_6\right]}_2$

$1\times$ Moles of ${\mathrm{K}}_2{\mathrm{CO}}_3=12\times$ Moles of ${\mathrm{K}}_2{\mathrm{Zn}}_3{\left[\mathrm{Fe}(\mathrm{CN}{)}_6\right]}_2$

(Q 1 mole of ${\mathrm{K}}_2{\mathrm{CO}}_3$ contains 1 moles of C ) $\frac{\text{ wt. of }{\mathrm{K}}_2{\mathrm{CO}}_3}{\text{ mol. wt of }{\mathrm{K}}_2{\mathrm{CO}}_3}=12\times \frac{\text{ wt. of the product }}{\text{ mol. wt. of product }}$ wt. of ${\mathrm{K}}_2{\mathrm{Zn}}_3{\left[\mathrm{Fe}(\mathrm{CN}{)}_6\right]}_2=\frac{27.6}{138}\times \frac{698}{12}=11.6\mathrm{g}$