Chemistry - Stoichiometry Question with Solution | TestHub

${\mathrm{MnO}}_2+4\mathrm{HCl}\to {\mathrm{MnCl}}_2+2{\mathrm{H}}_2\mathrm{O}+{\mathrm{Cl}}_2$

Moles $\frac{261}{87}=3$

$\mathrm{n}=\frac{1\times 448}{0.0821\times 546}$

$\mathrm{n}=10$

1. HCl is limiting reagent.

2. moles of chlorine produced = 2.5 (using HCl as L.R.) Molecules of chlorine = 2.5 × 6 × 10²³ = 15 × 10²³.

3. Moles of MnO₂ left = 3 – 2.5 = 0.5