Chemistry - Stoichiometry Question with Solution | TestHub

ChemistryStoichiometryBasic Methods of Calculations (POAC, LR)Medium2 minQB

ChemistryMediumsingle choice

Passage / Comprehension

Answer questions by appropriately matching the information given in the three columns of the following table.

Select only correct combination -

Answer:

Solution:

(i)

$N_{2} left = 0.2 - \frac{0.5}{3} = \frac{1}{30}$

(ii) $C + 2 H_{2} ⟶ CH_{4}$

(L.R.)

0.2mol 0.2 mol

0.1 mol left

(iii) $\displaylines CO + \frac{1}{2} O_{2} ⟶ C O_{2}$

(L.R.)

0.1 mol 0.1 mol

$l e f t = \frac{0.1}{2}$

(iv) $P_{4} + 3 O_{2} ⟶ P_{4} O_{6}$

(L.R.)

0.05 mol 0.05 mol

$l e f t = 0.05 - \frac{0.05}{3} = \frac{1}{30}$

Stream:JEESubject:ChemistryTopic:StoichiometrySubtopic:Basic Methods of Calculations (POAC, LR)

⏱ 2mℹ️ Source: QB

Loading discussions...