Chemistry - Solid State Question with Solution | TestHub

$\mathrm{P}\to 1,4,5$

$2{\mathrm{BeCl}}_2+{\mathrm{LiAlH}}_4\to 2{\mathrm{BeH}}_2+\mathrm{LiCl}+{\mathrm{AlCl}}_3$

${\mathrm{BeH}}_2$ is electron deficient and polymeric in solid state.

${\mathrm{BeH}}_2$ is a strong reducing agent and covalent and polymeric (bridged) in solid state

$\mathrm{Q}\to 2,4,5$

$\mathrm{BeO}+\mathrm{C}+{\mathrm{Cl}}_2\stackrel{600-800\mathrm{K}}{\to }{\mathrm{BeCl}}_2+\mathrm{CO}$

CO is a gas.

$\mathrm{R}\to 5$

$\mathrm{Be}(\mathrm{OH}{)}_2+2\mathrm{HCl}+2{\mathrm{H}}_2\mathrm{O}\to {\mathrm{BeCl}}_2+4{\mathrm{H}}_2\mathrm{O}$

${\mathrm{Be}}^{2+}$ in aqueous solution forms : ${\left[\mathrm{Be}{\left({\mathrm{H}}_2\mathrm{O}\right)}_4\right]}^{2+}$

Be here is ${\mathrm{sp}}^3$ hybridized

$\mathrm{S}⟶2,3$

$2\mathrm{Be}{\left({\mathrm{NO}}_3\right)}_2\to 2\mathrm{BeO}+4{\mathrm{NO}}_2+{\mathrm{O}}_2$

Total gaseous moles $=5$