A transition metal M can exist in two oxidation states +2 and +3 . It forms an oxide whose experimental formula is given by M x O where x

Question

A transition metal M can exist in two oxidation states +2 and +3 . It forms an oxide whose experimental formula is given by M x ​ O where x < 1 . Then the ratio of metal ions in +3 state to those in +2 state is given by -

TestHub · Accepted Answer

M x ​ O is formed by + 2 & + 3 ​ O.N. of M is = + x 2 ​ ​ ​ ​ ​ ​ ​ ​ ​ ​ i f ( + 2 ) ha s ( a % ) & ( + 3 ) ha s ( 100 − a ) % + x 2 ​ = 100 a × 2 ​ + 100 3 ( 100 − a ) ​ 200 = 2 a x + 300 x − 3 a x 200 = 300 x − a x x ( 3 x − 2 ) 100 ​ f or ( + 2 ) + 3 i s 100 − a = x 100 − ( 3 x − 2 ) 100 ​ = 100 [ x x − 3 x + 2 ​ ] = x 200 ( 1 − x ) ​ R a t i o o f + 2 & + 3 = 3 x − 2 2 ( 1 − x ) ​

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