Chemistry - Solid State Question with Solution | TestHub
Match the type of unit cell given in List-I with the features given in List-II.
List - I | List - II |
|---|---|
(P) Primitive cubic unit cell | (1) Each of the three perpendicular edges compulsorily have the different edge length i.e; . |
(Q) Body centred cubic unit cell | (2) Number of atoms per unit cell is one. |
(R) Face centred cubic unit cell | (3) In addition to the contribution from the corner atoms the number of atoms present in a unit cell is three. |
(S) End centred orthorhombic unit cell | (4) In addition to the contribution from the comer atoms the number of atoms present in a unit cell is one. |
Options:
Answer:
Solution:
In a primitive cubic (P) lattice, there are only 8 corner atoms. The contribution from these atoms is atom. Therefore, P → 2.
In a body-centered cubic (Q) lattice, in addition to the corner atoms, there is 1 atom at the body center. This gives an extra one atom. Therefore, Q → 4.
In a face-centered cubic (R) lattice, in addition to the corner atoms, there are 6 face-centered atoms. The contribution from these atoms is atoms. Therefore, R → 3.
In an end-centered orthorhombic (S) lattice, where , the contribution from the end-centered atoms is 1 atom. Therefore, S → 1,4.
Thus, the correct matching is: P→2, Q→4, R→3, S→1,4.
Hence, Option (D) is correct.