Chemistry - Solid State Question with Solution | TestHub

ChemistrySolid StateBasic Crystal System and Bravais LatticesMedium2 minQB
ChemistryMediummatching list

Match the type of unit cell given in List-I with the features given in List-II.

List - I

List - II

(P) Primitive cubic unit cell

(1) Each of the three perpendicular edges compulsorily have the different edge length i.e; .

(Q) Body centred cubic unit cell

(2) Number of atoms per unit cell is one.

(R) Face centred cubic unit cell

(3) In addition to the contribution from the corner atoms the number of atoms present in a unit cell is three.

(S) End centred orthorhombic unit cell

(4) In addition to the contribution from the comer atoms the number of atoms present in a unit cell is one.

Options:

Answer:
D
Solution:

In a primitive cubic (P) lattice, there are only 8 corner atoms. The contribution from these atoms is atom. Therefore, P → 2.

 

In a body-centered cubic (Q) lattice, in addition to the corner atoms, there is 1 atom at the body center. This gives an extra one atom. Therefore, Q → 4.

 

In a face-centered cubic (R) lattice, in addition to the corner atoms, there are 6 face-centered atoms. The contribution from these atoms is atoms. Therefore, R → 3.

 

In an end-centered orthorhombic (S) lattice, where , the contribution from the end-centered atoms is 1 atom. Therefore, S → 1,4.

 

Thus, the correct matching is: P→2, Q→4, R→3, S→1,4.

 

Hence, Option (D) is correct.

Stream:JEESubject:ChemistryTopic:Solid StateSubtopic:Basic Crystal System and Bravais Lattices
2mℹ️ Source: QB

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