Chemistry - Solid State Question with Solution | TestHub

For Nacl type crystals
$a=2\left({\text{r}}_{\text{cation}}\text{+}{\text{r}}_{\text{anion}}\right)$
$\Rightarrow {\text{r}}_{\text{cation}}\text{+}{\text{r}}_{\text{anion}}=\frac{a}{2}=\frac{537}{2}=268.5\text{pm}\text{.}$