Chemistry - Solid State Question with Solution | TestHub
ChemistrySolid StateCubic CrystalsMedium2 minQB
ChemistryMediumsingle choice
Passage / Comprehension
In diamond structure, carbon atoms form fcc lattice and 50% of tetrahedral voids occupied by carbon atoms. Every carbon atom is surrounded tetrahedrally by four carbon atoms with bond length 173.2 pm. On the basis
of above information answer following questions (NA = 6 × 1023 )
The side length of diamond unit cell is in (im pm)
Options:
Answer:
D
Solution:
Diamond structure mein carbon atoms FCC lattice banate hain aur 50% tetrahedral voids fill hote hain.
Diamond mein nearest C–C bond length = .
Given bond length = 173.2 pm.
So, .
Solving gives pm.
Stream:JEESubject:ChemistryTopic:Solid StateSubtopic:Cubic Crystals
⏱ 2mℹ️ Source: QB
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