Chemistry - Solid State Question with Solution | TestHub

Each molecule of$\mathrm{S}\mathrm{r}\mathrm{C}{\mathrm{l}}_2$develops a cation vacancy hence number of cation vacancy per mole NaCl
Total number of molecules$=\mathrm{n}\times {\mathrm{N}}_{\mathrm{A}}$
$=\frac{10^{-5}}{100}\times {\mathrm{N}}_{\mathrm{A}}$
Where${\mathrm{N}}_{\mathrm{A}}=6.023\times 10^{23}$
Total cationic vacancies = total molecules$\times$vacancies created by 1 molecule
$=\frac{10^{-5}}{100}\times {\mathrm{N}}_{\mathrm{A}}\times 1$
$=10^{-7}{\mathrm{N}}_{\mathrm{A}}$