If number of nearest neighbours, next nearest (2nd nearest) neighbours and next to next nearest ( $3^{rd}$ nearest) neighbours are $x, y$ and $z$ respectively for a given atom in face centered cubic unit cell, then calculate value of $\frac{x y}{z}$
Answer:
3
Solution:
$x = 12, y = 6, z = 24$

Question

If number of nearest neighbours, next nearest (2nd nearest) neighbours and next to next nearest ( $3^{rd}$ nearest) neighbours are $x, y$ and $z$ respectively for a given atom in face centered cubic unit cell, then calculate value of $\frac{x y}{z}$

Answer:

3

Solution:

$x = 12, y = 6, z = 24$

TestHub · Accepted Answer

x = 12 , y = 6 , z = 24

Chemistry - Solid State Question with Solution | TestHub

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