Chemistry - Redox Reactions Question with Solution | TestHub

ChemistryRedox ReactionsProblem involving Equivalent ConceptMedium2 minQB

ChemistryMediumsingle choice

In an acidic solution, $I^{-}$ changes to $I_{2}$ . How many grams of $I_{2}$ is produced if, in the same process, 3.0 × $1 0^{22}$ electrons are used up to reduce $H_{3} As O_{4}$ to $H_{3} As O_{3}$ ? (I = 127)

Options:

Answer:

Solution:

Moles of electrons = (3.0 × $1 0^{22}) / (6$ × $1 0^{23}$ ) = 0.05 mol. $2 I^{-}$ $\to$ $I_{2}$ + $2 e^{-}$ , so moles of $I_{2}$ = 0.05/2 = 0.025. Mass = 0.025 × 254 = 6.35 ≈ 6.4 g. Hence (d).

Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Problem involving Equivalent Concept

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