Chemistry - Redox Reactions Question with Solution | TestHub
ChemistryRedox ReactionsDouble IndicatorHard2 minQB
ChemistryHardnumerical
If 25 ml of 0.1 M solution of sodium sesquicarbonate () is titrated against 0.05 M - , using (i) phenolphthalein and (ii) methyl orange as indicators, what difference in titre values (in ml) would be recorded?
Answer:
100.00
Solution:
Salt = = 2.5 mmol 2.5 mmol + 2.5 mmol . Phenolphthalein: = 2.5 mmol 2.5/0.05 = 50 ml. Methyl orange: = + 2.5 = 7.5 mmol 150 ml. Difference = 100 ml. Ans 0100.
Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Double Indicator
⏱ 2mℹ️ Source: QB
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