Chemistry - Redox Reactions Question with Solution | TestHub
ChemistryRedox ReactionsTitrationMedium2 minQB
ChemistryMediumsingle choice
Passage / Comprehension
KMnO₄ oxidizes Xⁿ⁺ ion to XO₃⁻ in acid solution. 2.5×10⁻³ mole of Xⁿ⁺ requires 1.5×10⁻³ mole of MnO₄⁻.
What is the value of n?
Options:
Answer:
B
Solution:
X goes from +n to +5 (in XO₃⁻), losing (5 - n) e⁻; MnO₄⁻ Mn²⁺ gains 5 e⁻ in acid. Equivalents: 2.5×10⁻³(5 - n) = 1.5×10⁻³ × 5, so 5 - n = 3 and n = 2, matching (b).
Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Titration
⏱ 2mℹ️ Source: QB
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