In the reaction: P₄ + NaOH + H₂O → PH₃ + NaH₂PO₂, the equivalent weight of P₄ is

Disproportionation: one P goes 0 → -3 (gains 3 e⁻) and three P go 0 → +1 (lose 1 e⁻ each). Balanced: P₄ + 3NaOH + 3H₂O → PH₃ + 3NaH₂PO₂; 3 e⁻ transferred per P₄. n = 3, Eq wt = M/3. Hence (b).

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Chemistry - Redox Reactions Question with Solution | TestHub

ChemistryRedox ReactionsEquivalent Weight and n-factorEasy2 minQB

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In the reaction: P₄ + NaOH + H₂O $\to$ PH₃ + NaH₂PO₂, the equivalent weight of P₄ is

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Solution:

Disproportionation: one P goes 0 $\to$ -3 (gains 3 e⁻) and three P go 0 $\to$ +1 (lose 1 e⁻ each). Balanced: P₄ + 3NaOH + 3H₂O $\to$ PH₃ + 3NaH₂PO₂; 3 e⁻ transferred per P₄. n = 3, Eq wt = M/3. Hence (b).

Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Equivalent Weight and n-factor

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