In the reaction: K 2 C r 2 O 7 + 14HCl → 2KCl + 2CrC l 3 + 3C l 2 + 7 H 2 O , the equivalent weight of HCl is

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Chemistry - Redox Reactions Question with Solution | TestHub

ChemistryRedox ReactionsEquivalent Weight and n-factorHard2 minQB

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In the reaction: $K_{2} C r_{2} O_{7}$ + 14HCl $\to$ 2KCl + $2CrC l_{3}$ + $3C l_{2}$ + $7 H_{2} O$ , the equivalent weight of $HCl$ is

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Solution:

Cr(+6) $\to$ Cr(+3) for 2 Cr atoms takes 6 $e^{-}$ ; 6 of the 14 mol $HCl$ are oxidized to $3C l_{2}$ while 8 mol act as acid. 14 mol $HCl$ are consumed per 6 $e^{-}$ transferred, so Eq wt = 14M/6 = 7M/3. Hence (b).

Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Equivalent Weight and n-factor

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