In the reaction: Pb + PbO₂ + H₂SO₄ → PbSO₄ + H₂O, the equivalent weight of H₂SO₄ is

Balanced: Pb + PbO₂ + 2H₂SO₄ → 2PbSO₄ + 2H₂O. Pb(0) → Pb(+2) loses 2 e⁻ and PbO₂'s Pb(+4) → Pb(+2) gains 2 e⁻; 2 mol H₂SO₄ take part per 2 e⁻ transferred, so 1 mol per equivalent. Eq wt = M. Hence (a).

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Chemistry - Redox Reactions Question with Solution | TestHub

ChemistryRedox ReactionsEquivalent Weight and n-factorEasy2 minQB

ChemistryEasysingle choice

In the reaction: Pb + PbO₂ + H₂SO₄ $\to$ PbSO₄ + H₂O, the equivalent weight of H₂SO₄ is

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Balanced: Pb + PbO₂ + 2H₂SO₄ $\to$ 2PbSO₄ + 2H₂O. Pb(0) $\to$ Pb(+2) loses 2 e⁻ and PbO₂'s Pb(+4) $\to$ Pb(+2) gains 2 e⁻; 2 mol H₂SO₄ take part per 2 e⁻ transferred, so 1 mol per equivalent. Eq wt = M. Hence (a).

Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Equivalent Weight and n-factor

⏱ 2mℹ️ Source: QB

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