Chemistry - Redox Reactions Question with Solution | TestHub
ChemistryRedox ReactionsEquivalent Weight and n-factorMedium2 minQB
ChemistryMediumsingle choice
A sample of a metal carbonate was neutralized by 20 ml of 0.1 N and the resulting chloride gave 0.0873 g of phosphate, . The equivalent weight of M is
Options:
Answer:
B
Solution:
meq = 20 0.1 = 2 meq, so = 1 mmol and = 1/3 mmol. Molar mass = 0.0873 3000 = 262 = 3M + 190, so M = 24. Equivalent weight = 24/2 = 12, option (b).
Stream:JEESubject:ChemistryTopic:Redox ReactionsSubtopic:Equivalent Weight and n-factor
⏱ 2mℹ️ Source: QB
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