Chemistry - Real Gas Question with Solution | TestHub
ChemistryReal GasCompressibility FactorEasy2 minQB
ChemistryEasysingle choice
The equation of state for a gas is P(V − nb) = nRT, where b and R are constants. If the pressure and temperature are such that Vₘ = 5 b, what is the compressibility factor of gas in this condition?
Options:
Answer:
D
Solution:
With V = 5nb: P(5nb - nb) = nRT ⇒ 4bP · n = nRT ⇒ RT = 4bP. Then Z = (PVₘ)/(RT) = (5bP)/(4bP) = 5/4. Ans: (d)
Stream:JEESubject:ChemistryTopic:Real GasSubtopic:Compressibility Factor
⏱ 2mℹ️ Source: QB
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