Chemistry - Real Gas Question with Solution | TestHub
ChemistryReal GasVander Waal's Gas EquationMedium2 minQB
ChemistryMediumnumerical
The van der Waal's constants a and b for a gas of molar mass 164.2 g/mol are 4.105 atm-L2/mol2 and 0.1 L/mol, respectively. The density (in kg/m3) of the gas at 2 atm and 500 K is
Answer:
8.00
Solution:
(P + a/Vm2)(Vm - b) = RT, with RT = 0.0821 × 500 = 41.05 L-atm/mol.
(2 + 4.105/Vm2)(Vm - 0.1) = 41.05.
Trial Vm = 20.5 L: (2 + 4.105/420.25)(20.4) = (2.0098)(20.4) = 41.0. So Vm = 20.5 L/mol.
Density = 164.2 g / 20.5 L = 8.0 g/L = 8 kg/m3.
Stream:JEESubject:ChemistryTopic:Real GasSubtopic:Vander Waal's Gas Equation
⏱ 2mℹ️ Source: QB
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