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ChemistryReal GasVander Waal's Gas EquationMedium2 minQB
ChemistryMediumsingle choice

Under what pressure will carbon dioxide have the density of 2.2 g/litre at 300 K? For CO2, a = 3.6 atm l2 mol-2 and b = 0.05 mol-1 l.

Options:

Answer:
A
Solution:

Molar volume Vm = 44/2.2 = 20 l. Van der Waals: (P + a/(Vm2))(Vm - b) = RT gives (P + 3.6/400)(20 - 0.05) = 0.0821 × 300, i.e. P + 0.009 = 24.63/19.95 = 1.2346, so P = 1.226 ≈ 1.23 atm. Ans: (a)

Stream:JEESubject:ChemistryTopic:Real GasSubtopic:Vander Waal's Gas Equation
⏱ 2mℹ️ Source: QB

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