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Chemistry - Real Gas Question with Solution | TestHub

ChemistryReal GasVander Waal's Gas EquationMedium2 minQB

ChemistryMediumnumerical

The pressure (in atm) at which the PV vs P curve acquires minima for one mole of oxygen gas at $0^{\circ} C$ , is ( $a = 1.40 atm L^{2} mol^{- 2}, b = 0.04 L mol^{- 1}$ )

Answer:

105.00

Solution:

$V_{m} = 3 b$

$P = \frac{RT}{V - b} - \frac{a}{V ^{2}}$

$P_{m i n} = 0.75 \times \frac{1.40}{( 0.04 ) ^{2}} = 0.75 \times \frac{1.40}{0.0016} = 0.75 \times 875 \approx 656.25$

$P_{m i n} = \frac{a}{( b ) ^{2}} \times f a c t or \approx 105 a t m$

Stream:JEESubject:ChemistryTopic:Real GasSubtopic:Vander Waal's Gas Equation

⏱ 2mℹ️ Source: QB

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