Critical constants for a real (van der Waals) gas are given as
$T_{c}$ = 150 K ; $V_{c}$ = 0.099 L/mol ; $P_{c}$ = 46.7 atm.
[Take R = 0.0821 L atm $K^{- 1} mol^{- 1}$ ]
The correct statements for the gas are:

Question

Critical constants for a real (van der Waals) gas are given as

$T_{c}$ = 150 K ; $V_{c}$ = 0.099 L/mol ; $P_{c}$ = 46.7 atm.

[Take R = 0.0821 L atm $K^{- 1} mol^{- 1}$ ]

The correct statements for the gas are:

TestHub · Accepted Answer

V c ​ = 3b, so b = 0.099/3 = 0.033 L/mol: (A) true. T c ​ = 8a/(27Rb) gives a = 27 × 0.0821 × 0.033 × 150/8 = 1.37 atm L 2 / mol 2 . Boyle temperature T B ​ = a/(Rb) = (27/8) T c ​ = 27 × 150/8 = 506 K: (B) true. A gas can be liquefied by pressure only below T c ​ . 140 K < 150 K, so liquefaction is possible: (C) false, (D) true. Answer: (A), (B), (D).

Chemistry - Real Gas Question with Solution | TestHub

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