Chemistry - Real Gas Question with Solution | TestHub
ChemistryReal GasBoyle TemperatureHard2 minQB
ChemistryHardsingle choice
At moderate pressure, the compressibility factor for a gas is given as: Z = 1 + 0.25P − (150/T)·P, where P is in bar and T is in Kelvin. What is the Boyle's temperature of the gas?
Options:
Answer:
D
Solution:
Z = 1 + (0.25 - 150/T)P. At the Boyle temperature the coefficient of P vanishes: 0.25 = 150/T, so T = 150/0.25 = 600 K. Ans: (d)
Stream:JEESubject:ChemistryTopic:Real GasSubtopic:Boyle Temperature
⏱ 2mℹ️ Source: QB
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