Chemistry - Real Gas Question with Solution | TestHub

ChemistryReal GasVander Waal's Gas EquationHard2 minQB
ChemistryHardmultiple choice

The van der Waal's equation rearranged as a cubic in the molar volume Vₘ is

Vₘ³ − (b + RT/P)Vₘ² − (a/P)Vₘ − ab/P = 0

Indicate the correct statement(s):

Options:(select one or more)

Answer:
A, B, C
Solution:

Below Tc the cubic has three real roots (the outer two corresponding to liquid and vapour volumes) (a ✓); exactly at Tc the three roots merge into one, Vₘ = Vc (b ✓); above Tc only one real root survives, the other two being imaginary (c ✓). Hence (d) is false and the correct choices are (a), (b), (c).

Stream:JEESubject:ChemistryTopic:Real GasSubtopic:Vander Waal's Gas Equation
⏱ 2mℹ️ Source: QB

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