Chemistry - Real Gas Question with Solution | TestHub
ChemistryReal GasLiquification & Critical Constants of GasesEasy2 minQB
ChemistryEasyinteger
The equation of state for a certain gas is P = RT/(Vₘ − b) − a/Vₘ³, where a and b are constants distinct from zero. Ascertain whether the gas has a critical point or not. Answer as 1 if the gas has a critical point and as 2, if no critical point.
Answer:
1
Solution:
dP/dV = -RT/(V - b)² + 3a/V⁴ = 0 ⇒ RT = 3a(V - b)²/V⁴.
d²P/dV² = 2RT/(V - b)³ - 12a/V⁵ = 0 ⇒ RT = 6a(V - b)³/V⁵.
Equating: 6(V - b)/V = 3 ⇒ Vc = 2b, and then Tc = 3a/(16Rb²) > 0.
A real critical point exists. Answer = 1.
Stream:JEESubject:ChemistryTopic:Real GasSubtopic:Liquification & Critical Constants of Gases
⏱ 2mℹ️ Source: QB
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