Chemistry - PRACTICAL ORGANIC CHEMISTRY Question with Solution | TestHub

Percentage of chlorine in the organic compound=$\frac{\mathrm{atomic} \mathrm{mass} \mathrm{of} \mathrm{chlorine} \mathrm{X} \mathrm{mass} \mathrm{of} \mathrm{AgCl} \mathrm{formed} \mathrm{X} 100}{\mathrm{molecular} \mathrm{mass} \mathrm{ofAgCl} \mathrm{X} \mathrm{weight} \mathrm{of} \mathrm{organic} \mathrm{compound}}$

Mass of organic compound $=0.25 \mathrm{g}$

Mass of $\mathrm{AgCl}$ formed $=0.40 \mathrm{g}$

Mass of $\mathrm{Cl}$ in organic compound $=\frac{0.40\times 35.5}{143.5\times 0.25}$

Percentage of $\mathrm{Cl}$ in the compound $=\frac{0.40\times 35.5}{143.5\times 0.25}\times 100$

$=39.58\%$

Nearest integer=40.