In the sulphur estimation, 0.20 g of a pure organic compound gave 0.40 g of barium sulphate. The percentage of sulphur in the compound is ______ × 1 0 − 1 % . (Molar mass : O = 16 , S = 32 , Ba = 137

Question

In the sulphur estimation, 0.20 g of a pure organic compound gave 0.40 g of barium sulphate. The percentage of sulphur in the compound is ______ × 1 0 − 1 % . (Molar mass : O = 16 , S = 32 , Ba = 137 in g mol − 1 )

TestHub · Accepted Answer

Organic Compound ⟶ 0.20 gm ​ BaSO 4 ​ 0.40 gm 233 0.40 ​ mol ( BaSO 4 ​ ) 233 0.40 ​ mol (Sulphur) 233 0.40 ​ × 32 gm (sulphur) ​ % S = 0.20 233 0.40 × 32 ​ × 100 ​ = 27.5% or 275 × 1 0 − 1 %

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