Chemistry - Mole Concept Question with Solution | TestHub

$\underset{2\text{ moles }}{2{\mathrm{KClO}}_3}⟶\underset{2\text{ moles }}{2\mathrm{KCl}}+\underset{3\text{ moles }}{3{\mathrm{O}}_2}$

$3\times 32gm$ of O₂ is produced by heating 2 moles of KClO₃.

Therefore, $0.85g$ is produced by $\frac{0.85}{3\times 32}\times 2$ moles of KClO₃ $=0.0177$ moles of KClO₃.

Now, 2 moles of KClO₃ gives → $2$ moles of KCl.

This means $0.0177$ moles of KClO₃ will produce $\frac{0.0177\times 2}{2}$ moles of KCl

$=0.0177$ moles of KCl

$=0.0177\times 74.5gm$ of KCl

$=1.32gm$ of KCl.