Chemistry - Mole Concept Question with Solution | TestHub

$3NaOH+H_{3}P{O}_4\to N{a}_{3}P{O}_4+3H_{2}O$

required $0.49gm$

moles $=3\times 0.005=\frac{0.49}{98}$

moles $=0.015=0.005$ moles.

Moles of $NaOH=M_{NaOH}\times V_{NaOH}$ (litre).

$0.015=0.2\times V_{NaOH}$.

$V_{NaOH}=0.075l=75ml$.