Chemistry - Mole Concept Question with Solution | TestHub

Let relative abundance of$\mathrm{C}\mathrm{l}-37=\mathrm{x}\mathrm{\%}$
then relative abundance of$\mathrm{C}\mathrm{l}-35=(100-\mathrm{x})\mathrm{\%}$
Average atomic mass$=\frac{\mathrm{x}\times 37+(100-\mathrm{x})35}{100}35.5$
$37\mathrm{x}+3500-35\mathrm{x}=3550$
$\mathrm{x}=25$
So$100-\mathrm{x}=75$
Thus, the ratio of Cl-37 and Cl-35 is$\mathrm{x}:(100-\mathrm{x})=25:75$
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