Chemistry - Mole Concept Question with Solution | TestHub

ChemistryMole ConceptCalculation of moleEasy2 minQB

ChemistryEasysingle choice

How many moles of electron weigh one kilogram? ( $N_{AV} =$ Avogadro's no. $= 6.023 \times 1 0^{23}$ )

Answer:

Solution:

$9.1 \times 1 0^{- 31} k g$ is the mass of one electron

The mass of one mole of electrons is $(9.1 \times 1 0^{- 31} \times 6.023 \times 1 0^{23}) k g$ .

Therefore, $1 k g$ is the mass of:

$\frac{1}{9.1 \times 1 0 ^{- 31} \times 6.023 \times 1 0 ^{23}} m o l eso f e^{-} = \frac{1}{9.1 \times 6.023} \times 1 0^{8} m o l eso f e^{-}$

Stream:JEESubject:ChemistryTopic:Mole ConceptSubtopic:Calculation of mole

⏱ 2mℹ️ Source: QB

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