Equal weights of mercury and iodine are allowed to react completely to form a mixture of mercurous and mercuric iodide leaving none of the reactants. If the the ratio by weight of $Hg_{2} I_{2}$ and $HgI_{2}$ formed as x : $ℓ$ , find x.
(Hg = 200 , I = 127)

Question

Equal weights of mercury and iodine are allowed to react completely to form a mixture of mercurous and mercuric iodide leaving none of the reactants. If the the ratio by weight of $Hg_{2} I_{2}$ and $HgI_{2}$ formed as x : $ℓ$ , find x.

(Hg = 200 , I = 127)

TestHub · Accepted Answer

Let the masses of Hg₂I₂ = a g and HgI₂ = b g. Since equal masses of Hg and I react completely, a ( 654 400 ​ ) + b ( 454 200 ​ ) = a ( 654 254 ​ ) + b ( 454 254 ​ ) a ( 654 400 ​ − 654 254 ​ ) = b ( 454 254 ​ − 454 200 ​ ) a ( 654 146 ​ ) = b ( 454 54 ​ ) b a ​ = 146 × 454 54 × 654 ​ = 0.533 ≈ 0.53 Thus, x = 0.53 .

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