Chemistry - Mole Concept Question with Solution | TestHub

(i) 5 mole${\mathrm{O}}_2$required = 1 mole of${\mathrm{P}}_4$=124 gm${\mathrm{P}}_4$

for per gram,${\mathrm{O}}_2\mathrm{ }$required =$\frac{5}{124}\mathrm{ }\mathrm{m}\mathrm{o}\mathrm{l}\mathrm{e}\mathrm{ }$

(ii) 1 mole${\mathrm{O}}_2$required = 2 mole Mg =$2\times 24\mathrm{ }\mathrm{g}\mathrm{m}$

for per gram,${\mathrm{O}}_2\mathrm{ }$required$=\frac{1}{48}\mathrm{ }\mathrm{m}\mathrm{o}\mathrm{l}\mathrm{e}$

(iii) 3 mole${\mathrm{O}}_2$required = 2 mole Fe =$4\times 56\mathrm{ }\mathrm{g}\mathrm{m}$

for per gram Fe,${\mathrm{O}}_2$required$=\frac{3}{112\times 2}$mole

(iv) 5 mole${\mathrm{O}}_2$required -$=1$mole${\mathrm{C}}_3{\mathrm{H}}_8$=44 gm${\mathrm{C}}_3{\mathrm{H}}_8$

per gram${\mathrm{C}}_3{\mathrm{H}}_8,\mathrm{ }{\mathrm{O}}_2$required$=\frac{5}{44}$mole